7 FE Electrical and Computer Practice Problems with Solutions
In this article, we are discussing 5 important sample questions of FE electrical and computer CBT exam with detailed solutions. Read FE Electrical and Computer Practice Problems answers below.
Q1. The only point of inflection on the curve representing the equation y = x3 + x2 – 3 is at:
A. x = -2/3
B. x = -1/3
C. x = 0
D. x = 1/3
Solution:
f(x) = x3 + x2 – 3
Inflection point occurs when f “(x) = 0
f'(x) = 3x2 + 2x
f “(x) = 6x + 2
Set equal to zero
6x + 2 = 0
x = –1/3
f “(x) is negative below x = –1/3 and positive above x = –1/3
Since f “(x) = 0 and f “(x) changes signs at x = –1/3, the inflection point is at x = –1/3.
THE CORRECT ANSWER IS: B
Q2. As a professional engineer originally licensed 30 years ago, you are asked to evaluate a newly developed computerized control system for a public transportation system. You may accept this project if:
A. you are competent in the area of modern control systems
B. you do not live in the jurisdiction where the transportation system is being installed
C. your original area of specialization was in transportation systems
D. you have regularly attended meetings of a professional engineering society
Solution:
Refer to the NCEES Rules of Professional Conduct.
THE CORRECT ANSWER IS: A
Q3. If $500 is invested at an annual interest rate of 8% per year, its future worth at the end of 30 years will be most nearly:
A. $1,200
B. $1,700
C. $5,031
D. $15,000
Solution:
F = 500(F/P, 8%, 30)
= 500 (10.0627)
= $5,031
THE CORRECT ANSWER IS: C
Q4. In the circuit shown, voltage V0 (V) is most nearly:
A. 19.5
B. 18.5
C. 16.5
D. 3.0
Apply KCL to the node marked V0:
19.5
THE CORRECT ANSWER IS: A
Q5. An industrial plant load is rated at 2.8 MVA at 0.7 pf lagging. If a capacitor bank rated at 3 MVA is added to the load, the new overall power factor of the system is most nearly:
A. 0.9 leading
B. 0.9 lagging
C. 0.6 leading
D. 0.6 lagging
Solution
PL = 2.8 (0.7) = 1.96 MW
QL = 2.8 sin[cos–1 0.7] = 2 Mvar
SL = PL + jQL = 1.96 + j2 MVA
S = SL + SC = (1.96 + j2) + (–j3) = 1.96 – j1 = 2.2 ∠–27° MVA
pf = cos(–27°) = 0.89 leading
Q6. Which of the following is true of the electric field intensity about an isolated point charge?
A. It varies directly as the distance to the charge.
B. It varies inversely as the distance to the charge.
C. It varies directly as the square of the distance to the charge.
D. It varies inversely as the square of the distance to the charge.
Solution:
The formula for electric field intensity can be found in Electrostatic Fields in the Electrical and Computer Engineering section of the FE Reference Handbook.
This formula is where r is the distance. Since r2 is in the denominator, E varies inversely as the square of the distance to the charge.
THE CORRECT ANSWER IS: D
The binary number 1011 corresponds to the decimal number:
A. 3
B. 10
C. 11
D. 15
Solution
1011 = (1×23) + (0x22) + (1×2) + (1×20)
= 8 + 0 + 2 + 1 = 11
