# Production of Rotating Magnetic Field

- Link: https://studyelectrical.com/2014/01/production-of-rotating-magnetic-field.html
- Published: 2014-01-23T13:42:00+00:00
- Author: 

The production of Rotating magnetic field in 3 phase supply is very interesting.

When a 3-phase winding is energized from a 3-phase supply, a rotating magnetic field
is produced. This field is such that its poles do no remain in a fixed position 
on the stator but go on shifting their positions around the stator. For this reason,
it is called a rotating field.

It can be shown that the magnitude of this rotating field is constant and is equal
to **1.5 **fm where fm is the maximum flux due to any phase.

A three-phase induction motor consists of three phases winding as its stationary
part called stator. The three-phase stator winding is connected in star or delta.

The three-phase windings are displaced from each other by 120°. The windings are
supplied by a balanced three phase ac supply. 

![WP 20140123 17 23 00 Pro 1390480376 106.76.50.168](http://1.bp.blogspot.com/-36B-
3g8DIMk/UuEMUKLdEYI/AAAAAAAAAtI/cT3tGKfXUQA/s1600/WP_20140123_17_23_00_Pro__1390480376_106.76.50.168.
jpg)

 

The three-phase currents flow simultaneously through the windings and are displaced
from each other by 120° electrical. Each alternating phase current produces its 
own flux which is sinusoidal.

So all three fluxes are sinusoidal and are separated from each other by 120°.

If the phase sequence of the windings is R-Y-B, then mathematical equations for 
the instantaneous values of the three fluxes Φ_(R , )Φ_(Y ,)Φ_(B) can be written
as,

   Φ_(R )=  Φmsin(ωt)                

Φ_(Y )=  Φmsin(ωt – 120) 

Φ_(B) _( )=  Φmsin(ωt – 240)

As windings are identical and supply is balanced, the magnitude of each flux is 
Φm .  

![Phasor diagram of three phase](https://studyelectrical.com/wp-content/uploads/
2014/01/Phasor-diagram-of-three-phase.jpg)

 Waveforms of three fluxes and their positive directions

 

### Case 1 : ωt = 0

Φ_(R )=  Φmsin(0) =  0

Φ_(Y )=  Φmsin(0 – 120) =  -0.866 Φm

Φ_(B) _( )=  Φmsin(0 – 240) = +0.866 Φm

### Case 2 : ωt = 60

Φ_(R )=  Φmsin(60) =  +0.866 Φm

Φ_(Y )=  Φmsin(- 60) =  -0.866 Φm

Φ_(B) _( )=  Φmsin(- 180) = 0

### Case 3 : ωt = 120

Φ_(R )=  Φmsin(120) =  +0.866 Φm

Φ_(Y )=  Φmsin(0) =  0

Φ_(B) _( )=  Φmsin(- 120) = -0.866 Φm

### Case 4 : ωt = 180

Φ_(R )=  Φmsin(180) =  0

Φ_(Y )=  Φmsin(60) =  +.866 Φm

Φ_(B) _( )=  Φmsin(- 60) = -0.866 Φm

![Rotating magnetic field magnitude](https://studyelectrical.com/wp-content/uploads/
2014/01/Rotating-magnetic-field-magnitude.jpg)

By comparing the electrical and phasor diagrams we can find the flux rotates one
complete 360 degrees on the 180-degree displacement of flux. 

[⌊WP 20140123 17 27 33 Pro⌉⌊WP 20140123 17 27 33 Pro⌉[

 

### Speed of Rotating Magnetic Field

The speed at which the rotating magnetic field revolves is called the **synchronous
speed (N_(s))**.

Referring to the waveform of three phases, the time instant 4 represents the completion
of one quarter cycle of alternating current I x from the time instant 1.

During this one-quarter cycle, the field has rotated through 90°. At one complete
cycle of current I_(x) from the origin, the field has completed one revolution.

Therefore, for a 2-pole stator winding, the field makes one revolution in one cycle
of current. In a 4-pole stator winding, it can be shown that the rotating field 
makes one revolution in two cycles of current.

In general, for P poles, the rotating field makes one revolution in P/2 cycles of
current.

[latex] \therefore \quad Cycles\quad of\quad Current\quad =\quad \frac { P }{ 2 }\
quad \times \quad revolutions\quad of\quad field\quad [/latex]

[latex] or\quad Cycles\quad of\quad current\quad per\quad second\quad =\quad \frac{
P }{ 2 } \quad \times \quad revolutions\quad of\quad field\quad per\quad second [/
latex]

Since revolutions per second is equal to the revolutions per minute (N s ) divided
by 60 and the number of cycles per second is the frequency f,

[latex] f\quad =\quad \frac { P }{ 2 } \times \frac { { N }_{ S } }{ 60 } \quad 
=\quad \frac { { N }_{ S }P }{ 120 }[/latex]

[latex]\therefore \quad { N }_{ S }\quad =\quad \frac { 120f }{ P } [/latex]

The speed of the rotating magnetic field is the same as the speed of the alternator
that is supplying power to the motor if the two have the same number of poles. Hence
the magnetic flux is said to rotate at synchronous speed.

### Direction of Rotating Magnetic Field

The phase sequence of the three-phase voltage applied to the stator winding in the
first figure is R-Y-B.

If this sequence is changed to R-B-Y, it is observed that the direction of rotation
of the field is reversed i.e., the field rotates counterclockwise rather than clockwise.

However, the number of poles and the speed at which the magnetic field rotates remain
unchanged.

Thus it is necessary only to change the phase sequence in order to change the direction
of rotation of the magnetic field. For a three-phase supply, this can be done by
interchanging any two of the three lines.

As we shall see, the rotor in a [3-phase induction motor](https://studyelectrical.com/2014/11/how-three-phase-induction-motor-work.html)
runs in the same direction as the rotating magnetic field.

**Therefore, the direction of rotation of a [3-phase induction motor](https://studyelectrical.com/2014/11/how-three-phase-induction-motor-work.html)
can be reversed by interchanging any two of the three motor supply lines.**

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